Question

Como se resuelve los siguientes polinomios aritmeticos

a.3+18-5+2
b.(-3)+5-(-8)
c.(-2)x(-4)+(7)
d.[(-18+4)-(9-10)]-15
e.[(-9x4)-(-22-14)]÷9
f.-{[(8x-4)+(-5)]÷[(-11x2)+(-15)]}

Answer 1

a. 3 +18 -5 +2
23 - 5 = 18

b. (-3) +5 -(-8)
-3 +5 +8
-3 +13 = 10

c. (-2) × (-4) +(7)
-2 × -4 + 7
8 +7 = 15

d. [(-18 +4) -(9 -10)] -15
[-18 +4 -9 +10] -15
-18 +4 -9 +10 -15
-42 +14 = -28

e. [(-9 × 4) -(-22 -14)] ÷ 9
[-9 × 4 +22 +14] ÷ 9
[-36 +22 +14] ÷ 9
[-36 +36] ÷ 9
[ 0 ] ÷ 9 = 0

f. {[(8 × -4) + (-5)] ÷ [(-11 × 2) + (-15)]}
{[-32 -5] ÷ [ -22 -15]}
{[-37] ÷ [-37]}
-37 ÷ -37 = 1

Espero esté todo correcto.

Answer 2

a. 3 +18 -5 +2

23 - 5 = 18

b. (-3) +5 -(-8)

-3 +5 +8

-3 +13 = 10

c. (-2) × (-4) +(7)

-2 × -4 + 7

8 +7 = 15

d. [(-18 +4) -(9 -10)] -15

[-18 +4 -9 +10] -15

-18 +4 -9 +10 -15

-42 +14 = -28

e. [(-9 × 4) -(-22 -14)] ÷ 9

[-9 × 4 +22 +14] ÷ 9

[-36 +22 +14] ÷ 9

[-36 +36] ÷ 9

[ 0 ] ÷ 9 = 0

f. {[(8 × -4) + (-5)] ÷ [(-11 × 2) + (-15)]}

{[-32 -5] ÷ [ -22 -15]}

{[-37] ÷ [-37]}

-37 ÷ -37 = 1

Espero esté todo correcto.