Question

calcula aplicando la definicion de propiedades del logaritmo


a) log (1/3)
3

b)log 0,001

c) log 128
(1/2)

d) log (27/8)
(2/3)

e) log 3
81

f) log 64
4

Answer 1

$A)Log_{3} ( \frac{1}{3})= Log_{3}(1)- Log_{3}(3) =0-1=-1 \\ \\ B) Log_{10}( 0.001)= Log_{10} ( \frac{1}{1000} )= Log_{10} (1)-Log_{10}(1000) \\ 0-Log_{10}( 10^{3})=0-3=-3 \\ \\ E) Log_{3}(81)=Log_{3}( 3^{4} )=4 \\ \\ F) Log_{4} (64)=Log_{4}(4^{3})=3$