Question

cubo de
un binomio
(4a- 7)³


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Answer 1

Respuesta:

(4a−7)³

=(4a−7)*(4a−7)*(4a−7)

=(4a+−7)(16a²+−56a+49)

=(4a)(16a²)+(4a)(−56a)+(4a)(49)+(−7)(16a²)+(−7)(−56a)+(−7)(49)

=64a³−224a²+196a−112a²+392a−343

=64a³−336a²+588a−343

Explicación paso a paso: