Question

Alguien me ayuda urgente

Answer 1

a)

$\frac{x}{ \frac{10}{3} } = \frac{ \sqrt[3]{1 - \frac{37}{64} } }{ \frac{5}{18} } \\ \frac{x}{ 2 } = \frac{ \sqrt[3]{ \frac{27}{64} } }{ \frac{1}{6} } \\ \frac{x}{2} = 6 \times \frac{3}{4} \\ x = 9$

b)

$\frac{ \sqrt{( { \frac{1}{25} })^{ - 1} } }{x} = \frac{0. \frac{}{6} - 1}{6} \\ \frac{ \sqrt{25} }{x} = \frac{ \frac{6}{9} - 1}{6} \\ \frac{5}{x} = \frac{ - \frac{1}{3} }{6} \\ \frac{5}{x} = - \frac{1}{18} \\ x = 5 \times - 18 \\ x = - 90$

c)

$\frac{ \sqrt{3. \frac{}{9} } }{ {(3 + {4}^{2}) }^{0} } = \frac{x}{ {2}^{3} \times {2}^{ - 4} } \\ \frac{ \sqrt{4} }{1} = \frac{x}{ {2}^{3 - 4} } \\ 2 = \frac{x}{ {2}^{ - 1} } \\ 2 = 2x \\ x = 1$