Question

$\frac{7}{12}$ x 3³ x $\frac{1}{4}$² x $\frac{1}{2}$

Answer 1

$(\frac{7}{12})(3^{3})(\frac{1}{4})^{^{2} } (\frac{1}{2} )\\\\ ( \frac{7}{12})(27})(\frac{1}{16}) } (\frac{1}{2} )\\\\\frac{(7)(27)(1)(1)}{(12)(16)(2)} \\\\\frac{189}{384} \\\\\frac{63}{128}$

Eternamente axllxa