Question

2log2(x+1)-log4(x+1)=1

Answer 1

2log2(x+1)-log4(x+1)=1
2*[log2+log(x+1)]-[log4+log(x+1)]=1
2log2+2log(x+1)-log4-log(x+1)=1
2log2+2log(x+1)-log2²-log(x+1)=1
2log2+2log(x+1)-2log2-log(x+1)=1
2log(x+1)-log(x+1)=1
log(x+1)=1
10=x+1
x=9