Question

le doy coronita a quien me ayude con esto​

Answer 1

$a)\\\\x+\frac{16}{4} =\frac{48}{20}\\\\x+4=\frac{24}{10}\\\\x+4=\frac{12}{5}\\\\5( x+4=\frac{12}{5})\\\\5x+20=12\\\\5x=12-20\\\\5x=-8\\\\x=-\frac{8}{5}$

$b)\\\\\frac{2}{4} x-\frac{11}{2} =\frac{1}{2} (x+\frac{14}{12} )\\\\\frac{2x}{4} -\frac{11}{2} =\frac{1}{2} (\frac{12x}{12} +\frac{14}{12} )\\\\\frac{2x}{4} -\frac{11}{2} =\frac{1}{2} (\frac{12x+14}{12} )\\\\\frac{2x}{4} -\frac{11}{2} =\frac{12x+14}{24}\\\\\frac{x}{2} -\frac{11}{2} =\frac{12x+14}{24}\\\\\frac{x-11}{2} =\frac{12x+14}{24}\\\\\frac{x-11}{2} =\frac{6x+7}{12}\\\\2(\frac{x-11}{2} =\frac{6x+7}{12})\\\\x-11=\frac{6x+7}{6} \\\\6(x-11=\frac{6x+7}{6} )\\\\6x-66=6x+7\\6x-6x=7+66\\0=73\\\\falso$

Comprobación:

$\\ a)\\\\-\frac{8}{5} +\frac{16}{4} =\frac{48}{20} \\\\-\frac{32}{20} +\frac{80}{20} =\frac{48}{20} \\\\\frac{80-32}{20} =\frac{48}{20} \\\\\frac{48}{20} =\frac{48}{20}\\\\\frac{24}{10} =\frac{24}{10}\\\\\frac{12}{5} =\frac{12}{5}$

$b)\\\\\frac{2}{4}(73)-\frac{11}{2} = \frac{1}{2}(73+\frac{14}{12} )\\\\\frac{146}{4}-\frac{11}{2} =\frac{1}{2} (73+\frac{7}{6} )\\\\\frac{73}{2} -\frac{11}{2}=\frac{1}{2} (\frac{438}{6} +\frac{7}{6} ) \\\\\frac{62}{2}=\frac{1}{2}(\frac{445}{6} )\\\\\frac{62}{2}= \frac{445}{12} \\\\31=\frac{445}{12}\\\\falso$