Question

Método de Cramer Ayúdenmeeee

Answer 1

Explicación paso a paso:

$\left \{ {{2x-3y=-8} \atop {3x+2y=1}} \right.\\\\D=\left[\begin{array}{ccc}2&-3\\3&2\\\end{array}\right] \\\\D_{1} = \left[\begin{array}{ccc}-8&-3\\1&2\\\end{array}\right] \\\\D_{2} = \left[\begin{array}{ccc}2&-8\\3&1\\\end{array}\right] \\\\D= 13\\D_{1}=-13\\D_{2}= 26\\\\x= \frac{D_{1} }{D} , y=\frac{D_{2} }{D}\\X=-1\\Y=2\\\\Par Ordenado\\(x,y)=(-1,2)\\\\\left \{ {{2.(-1)-3.2=-8} \atop {3.(-1)+2.2=1}} \right. \\\\\left \{ {{-8=-8} \atop {1=1}} \right.\\\P. Ord- (x,y)=(-1,2)$

Answer 2

Respuesta:

x=-1  y=2

Explicación paso a paso: se multiplica cruzado

x=  8     -3

      1    2

--------------------- =

     2      -3

     3       2

x= (-8)(2)-(1)(-3)          -16  +3 = -13

---------------------------=--------------------- = -1

     (2)(2)-(3)(-3)     =   4+9    = 13

y=  2     -8

     3      1

--------------------- = (2)(1)-(3)(-8)  = 2+24 =26      26/13=2

  2         -3          (2)(2)-(3)(-9) = 4 + 5  = 13

  3           2