Question

Resolver las siguiente ecuaciones.
a) 2x + 3 = 9
b) 3x - 5 = 10
c) x + 4x = 7 + 13
d) 2 + 7x - 3x = 18
e) 9 + 5x - 4 + x = 23
f) 10x - 5 - 2x = 9 + 5x + 7

Answer 1

2x + 3 = 9 ↓↓

$2x + 3 = 9 \\ 2x = 9 - 3 \\ 2x = 6 \\ \frac{2x}{2} = \frac{6}{2} \\ x = 3$

3x - 5 = 10 ↓↓

$3x - 5 = 10 \\ 3x = 10 + 5 \\ 3x = 15 \\ \frac{3x}{3} = \frac{15}{3} \\ x = 5$

x + 4x = 7 + 13 ↓↓

$x + 4x = 7 + 13 \\ 5x = 20 \\ \frac{5x}{5} = \frac{20}{5} \\ x = 4$

2 + 7x - 3x = 18 ↓↓

$2 + 7x - 3x = 18 \\ 2 + 4x = 18 \\ 4x = 18 - 2 \\ 4x = 16 \\ \frac{4x}{4} = \frac{16}{4} \\ x = 4$

9 + 5x - 4 + x = 23 ↓↓

$9 + 5x - 4 + x = 23 \\ 5 + 5x + x = 23 \\ 5 + 6x = 23 \\ 6x = 23 - 5 \\ 6x = 18 \\ \frac{6x}{6} = \frac{18}{6} \\ x = 3$

10x - 5 - 2x = 9 + 5x + 7 ↓↓

$10x - 5 - 2x = 9 + 5x + 7 \\ 8−5=9+5+7 \\ 8−5=16+5 \\ 8−5=5+16 \\ 8−5=5+16+5 \\ 8=5+21 \\ 8−5=21 \\ 3x = 21 \\ \frac{3x}{3} = \frac{21}{3} \\ x = 7$