Question

6xcuadrada-42x=0

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Answer 1

Respuesta:

6x-42x=1764

$a = 6; b = 42; c = 0;\\Δ = b2-4ac\\Δ = 422-4·6·0\\Δ = 1764$

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=1764−−−−√=42

x1=−b−Δ√2a=−(42)−422∗6=−8412=−7

x2=−b+Δ√2a=−(42)+422∗6=012=0