Question

14x^2-19x-3=0 , primer valor de “x” y segundo valor de “x”
Aiuda xfa :(

Answer 1

X1=.142 X2=-1.5

ax²+bx-c=0

x=-b±√b²-4ac

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2a

x=-19±√19²-4(14)(-3)

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2(14)

x=-19±√19²-4(14)(-3)

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28

x=-19±√19²-4(-42)

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28

x=-19±√19²+168

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28

x=-19±√361+168

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28

x=-19±√529

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28

x=-19±23

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28

X1=-19+23

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28

X1=4

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28

X1=.142

X2=-19-23

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28

X2=-42

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28

X2=-1.5