Question

$f(x) = {x}^{2} - 4 \times x + 3 = 0$
doy corona​

Answer 1

Respuesta:

x=$\frac{-b+-\sqrt{b^{2}-4ac } }{2a}$

x=$\frac{-(-4)±\sqrt{(-4^{2})-4.1.3 } }{2.1}$

x=$\frac{4±\sqrt{16+12} }{2}$

x=$\frac{4±\sqrt{28} }{2}$

x1=$\frac{4+5,29}{2} = \frac{9,29}{2} =4,64$

x2=$\frac{4-5,29}{2} = \frac{-1,29}{2} =-0,64$

Explicación paso a paso: