Question

x³+2x²-4x-8

xfas ayudar​

Answer 1

$x³+2x²-4x-8 = \\ \\ {x}^{2} \times (x + 2) - 4(x + 2) = \\ \\ (x + 2) \times ( {x}^{2} - 4) = \\ \\ ( {x}^{2} ) \times (x - 2) \times (x + 2) = \\ \\ (x + 2) { }^{1} \times (x + 2) {}^{1} = \\ \\ (x + 2) {}^{1 + 1} = \\ \\ (x + 2) {}^{2} = \\ \\ (x + 2 {}^{} ) {}^{2} \times (x - 2)$