Question

tgx+ctgx=3. calcular: E= tg²x+ctg²x.
ashuuuudaaaa​

Answer 1

Respuesta:

6

Nos dan :tagx - ctgx =2

recuerda (tagx)(ctgx) =1

elevamos al cuadrado la ecuación

[ tagx - ctgx]^2 = 2^2

[(tagx)^2 - 2(tagx)(ctgx)+ (ctgx)^2] = (2)^2

(tagx)^2 + (ctgx)^2 - 2(1) = 4

(tagx)^2 + (ctgx) ^2 = 4 + 2

(tagx)^2 + (ctgx)^2 = 6