Question

me pueden ayudar porfavor es parahoy​

Answer 1

Explicación paso a paso:

${sen}^{6} + {cos}^{6} = 1 - 3 {sen}^{2} . {cos}^{2}$

$1 - 2 {sen}^{2} . {cos}^{2} = {sen}^{4} + {cos}^{4}$

$3(1 - {sen}^{2} \alpha . { \cos }^{2} \alpha ) +9 {sen}^{2} \alpha . {cos}^{2} \\ 3 - 3 {sen}^{2} \alpha . {cos}^{2} \alpha + 9 {sen}^{2} \alpha. {cos}^{2} \alpha \\ 3 + 6 {sen}^{2} \alpha . {cos}^{2} \alpha \\ 3(1 + 2 {sen}^{2} . {cos}^{2} ) \\ 3( {sen}^{4} \alpha + {cos}^{4} \alpha ) \\ 3 {sen}^{4} + 3 {cos}^{4} \alpha$

$3(1 - {sen}^{2} \alpha . { \cos }^{2} \alpha ) +9 {sen}^{2} \alpha . {cos}^{2} \\ 3 - 3 {sen}^{2} \alpha . {cos}^{2} \alpha + 9 {sen}^{2} \alpha. {cos}^{2} \alpha \\ 3 + 6 {sen}^{2} \alpha . {cos}^{2} \alpha \\ 3(1 + 2 {sen}^{2} . {cos}^{2} ) \\ 3( {sen}^{4} \alpha + {cos}^{4} \alpha ) \\ 3 {sen}^{4} + 3 {cos}^{4} \alpha$