Question

calcula el valor de x

ayúdenme es para hoy pliss​

Answer 1

Respuesta:

Solo usa teorema de Pitagóras

${h}^{2} = {c}^{2} + {c}^{2}$

h: hipotenusa

c: catetos

1)

${6}^{2} = {5}^{2} + {x}^{2} \\ 36 = 25 + {x}^{2} \\ 36 - 25 = {x}^{2} \\ 11 = {x}^{2} \\ \sqrt{11} = x$

2)

${x}^{2} = {4}^{2} + {9}^{2} \\ {x}^{2} = 16 + 81 \\ {x}^{2} = 97 \\ x = \sqrt{97}$

3) Le pongo 2 porque solo estoy usando la mitad de la base que es 4

${5}^{2} = {x}^{2} + {2}^{2} \\ 25 = {x}^{2} + 4 \\ 25 - 4 = {x}^{2} \\ 21 = {x}^{2} \\ \sqrt{21} = x$