Question

6x2 + 11 x-10=0 resolver con la fórmula general

Answer 1

Respuesta:

$6 {x}^{2} + 11x - 10 = 0 \\ \\ x = - b \frac{ + }{ - } \frac{ \sqrt{(b)^{2} - 4ac} }{2a} \\ \\ x = - 11 \frac{ + }{ - } \frac{ \sqrt{ {11}^{2} - 4(6)( - 10) } }{2(6)} \\ \\ x = - 11 \frac{ + }{ - } \frac{ \sqrt{ 121 + 240 } }{12} \\ \\ x = - 11 \frac{ + }{ - } \frac{ \sqrt{ 361 } }{12} \\ \\ x = - 11 \frac{ + }{ - } \frac{19}{12} \\ \\ x = - 11 + \frac{19}{12} = \frac{8}{12} = \frac{2}{3} \\ \\ x = - 11 - \frac{19}{12} = \frac{ - 30}{12} = - \frac{5}{2}$

Hola. Espero sea de ayuda!