Question

derivada de =(2senx-3cosx)∧3

Answer 1

$=3 (2senx-3cosx)^{2} (2cosx+3senx) \\ =3(4 (senx)^{2}-12senxcosx+9 (cosx)^{2})(2cosx+3senx) \\ =3(4(senx)^{2}+4 (cosx)^{2}+5 (cosx)^{2}-12senxcosx)(2cosx+3senx) \\ =3(4+5 (cosx)^{2}-12senxcosx)(2cosx+3senx) \\ =3[8cosx+12senx+10(cosx)^{3}+15senx(cosx)^{2}-24senx(cosx)^{2} \\ -36(senx)^{2}cosx] \\ =3[8cosx+12senx+10(cosx)^{3}-9senx(cosx)^{2}-36(senx)^{2}cosx] \\ =24cosx+36senx+30(cosx)^{3}-27senx(cosx)^{2}-108(senx)^{2}cosx$