Question

Si a=32a=32 y b=−2b=−2, el valor numérico de la expresión 2a−b2(1−b)2a−b2(1−b) es:

Answer 1

2a-b2(1-b)2a-b2(1-b)=
2(32) - (-2)2 (1-(-2)) 2(32) - (-2)2 (1-(-2)) =
64 -(-4)(1+2) (64) -(-4)(1+2)=
64 -(-4)(3) (64) -(-4)(3)=
64 -(-12) (64) -(-12)=
64 -(-768) +12=
64 +768 +12=
844