Question

3. tan x.sen x + cos x = sec x​

Answer 1

Explicación paso a paso:

$\tan( \alpha ) \times \sin( \alpha ) + \cos( \alpha ) = \sec( \alpha ) \\ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \times \sin( \alpha ) + \cos( \alpha ) = \sec( \alpha ) \\ \frac{ { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} }{ \cos( \alpha ) } = \sec( \alpha ) \\ {\sin( \alpha ) }^{2} + {\cos( \alpha ) }^{2} = \sec( \alpha ) \times \cos( \alpha ) \\ 1 = \frac{1}{ \cos( \alpha ) } \times \cos( \alpha ) \\ 1 = 1$

Verdadero; Si cumple la igualdad.