Question

a) 6x2 + 5x - 4 = 0​

Answer 1

Eᴄᴜᴀᴄɪᴏ́ɴ ᴄᴜᴀᴅʀᴀ́ᴛɪᴄᴀ

Resolvemos usando la formula general

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

Remplazamos los valores

$x=\frac{-5±\sqrt{5^{2}-4(6)(-4) } }{2(6)}$

$x=\frac{-5±\sqrt{25+96 } }{12}\\x=\frac{-5±\sqrt{121 } }{12}\\x=\frac{-5±11}{12}$

Sᴏʟᴜᴄɪᴏɴᴇs

$x_{1} =\frac{-5+11}{12} \\\\x_{1}=\frac{6}{12}$

$x_{2}=\frac{-5-11}{12} \\\\x_{2}= \frac{-16}{12}$