• Asignatura: Química
  • Autor: felixconcepcioncabal
  • hace 5 años

HALLA LA MASA MOLECULAR DE CADA COMPUESTO . H2CO3. (HNO3). H2CO2 NH3. ayúdenme pls

Respuestas

Respuesta dada por: gabymtzcollazo88
1

H3BO3

H: 3 x 1 = 3 g/mol

B: 1 X 10.8 = 10.8 g/mol

O: 3 x 16 = 48 g/mol

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          Mm = 61.8  g/mol

H2CO3

H: 2x 1 = 2 g/mol

C: 1 X 12 = 12 g/mol

O: 3 x 16 = 48 g/mol

``````````````````` `````````````

        Mm = 62  g/mol

AL2(SO4)3

Al: 2 x 27 = 54 g/mol

S: 3 x  32 = 96 g/mol

O: 12 x 16 = 192 g/mol

````````````````````````````````

        Mm = 342 g/mol

H3PO3

H: 3 x  1 = 3 g/mol

P: 1 x  31 = 31 g/mol

O: 3 x 16 = 48 g/mol

````````````````````````````````

        Mm = 82 g/mol

HNO3

H: 1 x1 = 1 g/mol

N: 1 x 14 = 14 g/mol

O: 3 x 16 = 48 g/mol

``````````````````````````````

        Mm = 63 g/mol

C6H12O6

C: 6 x 12 = 72 g/mol

H: 12  x 1 = 12 g/mol

O:  6 x 16 = 96 g/mol

``````````````````````````````````

        Mm = 180 g/mol

Respuesta dada por: mabazan21
0

Respuesta:

hola si no me equivoco es 62 uma

Explicación:

espero que te sirva

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