Question

Ayudaaaa
tema radicales

Answer 1

7+5=12

7x5=35

5+3=8

5x3=15

$\sqrt{12 - 2 \sqrt{35} } + \sqrt{8 + 2 \sqrt{15} } = \sqrt{a + \sqrt{b} } \\ \sqrt{7} - \sqrt{5} + \sqrt{5} + \sqrt{3} = \sqrt{a + \sqrt{b} } \\ \sqrt{7} + \sqrt{3} = \sqrt{a + \sqrt{b} } \\ \sqrt{10 + 2 \sqrt{21} } = \sqrt{a + \sqrt{b} } \\ \sqrt{10 + \sqrt{84} } = \sqrt{a + \sqrt{b} }$

a = 10

b = 84

b - 8a = 84 - 80 = 4