Question

resuelve los siguientes binomios (2m²+7)²= , (7x²-3y)²= , (x+13)(x-13)= , (7m³-5n⁴p²)(m³+5n⁴p²)=​

Answer 1

Respuesta:

$\left(2m^2+7\right)^2\\=\left(2m^2\right)^2+2\cdot \:2m^2\cdot \:7+7^2\\=4m^4+28m^2+49$

$\left(7x^2-3y\right)^2\\=\left(7x^2\right)^2-2\cdot \:7x^2\cdot \:3y+\left(3y\right)^2\\=49x^4-42x^2y+9y^2$

$\left(x+13\right)\left(x-13\right)\\=x^2-13^2\\=x^2-169$

$\left(7m^3-5n^4p^2\right)\left(m^3+5n^4p^2\right)\\=7m^3m^3+7m^3\cdot \:5n^4p^2+\left(-5n^4p^2\right)m^3+\left(-5n^4p^2\right)\cdot \:5n^4p^2\\=7m^3m^3+7\cdot \:5m^3n^4p^2-5m^3n^4p^2-5\cdot \:5n^4n^4p^2p^2\\=7m^6+30m^3n^4p^2-25n^8p^4$

Explicación: