1 ) ×2=-8y
2) y2=-16×
3) ×2+20y=0
Respuestas
Respuesta:
8X^{2}X
2
+ 8Y^{2}Y
2
-12X + 20Y + 17 = 0 ; X^{2} + Y^{2} - \frac{12}{8} X + \frac{20}{8} Y + \frac{17}{8} = 0X
2
+Y
2
−
8
12
X+
8
20
Y+
8
17
=0
X^{2} +Y^{2} - \frac{3}{2} X + \frac{5}{2} Y = - \frac{17}{8}X
2
+Y
2
−
2
3
X+
2
5
Y=−
8
17
; ((X^{2} - \frac{3}{2} X) + (Y^{2} + \frac{5}{2} Y) = - \frac{17}{8}(X
2
−
2
3
X)+(Y
2
+
2
5
Y)=−
8
17
Completamos cuadrados: (X^{2} - \frac{3}{2} + \frac{9}{16} ) + (Y^{2} + \frac{5}{2} + \frac{25}{16} = - \frac{34}{16} + \frac{9}{16} + \frac{25}{16}X
2
−
2
3
+
16
9
)+(Y
2
+
2
5
+
16
25
=−
16
34
+
16
9
+
16
25
((X^{2} - \frac{3}{2} } X + (\frac{3}{4}) ^{2} ) + (Y^{2} + \frac{5}{2} + ((\frac{5}{4}) ^{2} ) = 0
( X - 3/4)( X - 3/4) + (Y + 5/4)(Y + 5/4) = 0
( X - 3/4)>2 + (Y + 5/4)>2 = 0
h = 3/4 K = - 5/4 r = 0
A = πr>2 = πx0 = o
Pr = 2 π r = 2 π x 0 = 0