Question

HALLAR X DE LA ECUACION 4X SEN²60 + SEC²45= 7X SEC 60 - 9TG 45 x CSC30
AYUDENME CON ESTA POR FA

Answer 1

4x sen²60°+sec²45°=7x sec60°-9tg45°csc30°
4x(√3/2)²+(2/√2)²=7x(2)-9(1)(2)
4x(3/4)+(4/2)=14x-18
12x/4+2=14x-18
3x+2=14x-18
20=11x
20/11=x