Question

(a+b)²
(w+s)²
(2x+6)²
(8x+8)²
(4x+3y)²
(5x+2y)²​

Answer 1

Respuesta:

$(a+b)² = {a}^{2} + 2ab + {b}^{2} \\ (w+s)² = {w}^{2} + 2ws + {s}^{2} \\ (2x+6)² = {2}^{2} {x}^{2} + 2(2x)(6) + {6}^{2} = 4 {x}^{2} + 24x + 36 \\ (8x+8)² = {8}^{2} {x}^{2} + 2(8x)(8) + {8}^{2} = 64 {x}^{2} + 128x + 64 \\ (4x+3y)² = {4}^{2} {x}^{2} + 2(4x)(3y) + {3}^{2} {y}^{2} = 16 {x}^{2} + 24xy + 9 {y}^{2} \\ (5x+2y)² = {5}^{2} {x}^{2} + 2(5x)(2y) + {2}^{2} {y}^{2} = 25 {x}^{2} + 20xy + 4 {y}^{2}$