Question

ayudenme a resolver estas integrales................
1° ∫(x³-5 x$\frac{ x^{2} }{3 }$
2° ∫(x-6) /2 dx
3° ∫$\frac{5}{3}$ x² dx
4° ∫4$\sqrt{ x^{3} }$dx
5° ∫(x³+$\frac{2}{3}$x²+4x-$\sqrt{x}$)dx

Answer 1

$2) \frac{1}{2}( \int{x}dx-\int{6}dx)= \frac{1}{2} ( \frac{ x^{2}}{2} -6x)+C= \frac{ x^{2}}{4}-3x+C$

3) $\frac{5}{3}\int{ x^{2}}dx= \frac{5}{3}* \frac{ x^{3} }{3}+C= \frac{5x^{3}}{9} +C$

4) $4\int{ x^{3/2} }dx=4( \frac{2}{5}*x^{5/2})+C= \frac{8}{5} \sqrt{ x^{5} }+C=\frac{8}{5} x^{2} \sqrt{ x }+C$

5)$\int{ x^{3} }dx+ \frac{2}{3} \int{ x^{2}}dx+4\int{x}dx-\int{ x^{1/2} }dx=$
$\frac{ x^{4}}{4}+ \frac{2}{9} x^{3} + \frac{4}{2} x^{2}- \frac{2}{3} x^{3/2} +C$

$\int\ { x^{2}- \frac{5x}{3 x^{2} } } \, dx$ así es el primero? al enunciado me refiero..