Question

resuelve aplicando propiedad distributiba (28-16)%4=
7.(8-3+2)=
3. (10+6)=
(11-7).8=
(12-6)% 3=​

Answer 1

Respuesta:

• (28-16)%4 =  (28/4) - (16/4) = 7 - 4 = 3
• 7.(8-3+2) =  (7*8) - (7*3) + (7*2) = 56 - 21 + 14 = 49
• 3. (10+6) =  (3*10) + (3*6) = 30 + 18 = 48
• (11-7).8 =  (11*8) - (7*8) = 88 - 56 = 32
• (12-6)% 3 =​ (12/3) - (6/3) = 4 - 2 =2