\sqrt{} 5 {}^{2}  + 12 {}^{2}  - ( \sqrt{} 5) {}^{2}  =
( \sqrt{} 2 {}^{4} ) + ( \sqrt{3}  {}){ {}^{2} }  - 5 {}^{0}
Por favor ayudarme​

Respuestas

Respuesta dada por: kat388
1

=\sqrt{5^{2} } +12^{2} -(\sqrt{5})^{2}

=\sqrt{25} +12^{2} -(\sqrt{5} )^{2}

= 5+12^{2} -(\sqrt{5})^{2}

= 5+12^{2} -2.23^{2}

= 5+12^{2} -5

=5+144-5

=149-5

=144

---------------------------------------------

=(\sqrt{2^{4} })+(\sqrt{3})^{2} -5^{0}

=\sqrt{16} +(\sqrt{3 }})^{2} -5^{0}

=4 +(\sqrt{3 }})^{2}-5^{0}

=4 +{1.73}^{2}  -5^{0}

=4 +3-5^{0}

=4+3-1

=7-1

=6


inanonimoo: muchas gracias
kat388: de nada ;))
Preguntas similares