Question

es urgente por favor

Answer 1

a) $(\frac{1}{6}) ^{-2} (\frac{1}{2} -(\frac{2}{3} )^{0}) =$  6² · $(\frac{1}{2} - 1)$ = 36 · $(\frac{1}{2} -\frac{2}{2} )$ = 36 · $(-\frac{1}{2} )$ = -18

b) $\sqrt[4]{(-81)(-\frac{1}{16}) } + (\frac{5}{3}) ^{2} : (\frac{5}{3} )$ = $\sqrt[4]{\frac{3^{4} }{2^{4} } } +\frac{5}{3}$ = $\frac{3}{2} +\frac{5}{3} =\frac{9}{6} +\frac{10}{6} =\frac{19}{6}$

c) $-\frac{8}{3} x^{3} +\frac{1}{6} =-\frac{5}{2}$

$\frac{1}{6} +\frac{5}{2} =\frac{8}{3} x^{3}$

$\frac{8}{3} x^{3} =\frac{1}{6} +\frac{15}{6}$

$\frac{8}{3} x^{3} =\frac{16}{6}$

$\frac{8}{3} x^{3} =\frac{8}{3}$

$x^{3} =1$

x = 1

d) $\sqrt{\frac{2}{7}x } -5= -3$

$\sqrt{\frac{2}{7}x } =-3+5$

$\sqrt{\frac{2}{7} x} =2$

$(\sqrt{\frac{2}{7} x} )^{2} =2^{2}$

$\frac{2}{7} x=4$

$x=\frac{28}{2}$

x = 14