Question

6x²+5x-1=0
Con formula general​

Answer 1

Respuesta:

Formula cuadrática:

$\frac{-b+-\sqrt[2]{b^{2}-4(a)(c) } }{2(a)}$

a = 6 ; b = 5 ; c = -1

Remplazamos:

$\frac{-5+-\sqrt[2]{(5)^{2}-4(6)(-1) } }{2(6)}\\\frac{-5+-7}{2*6\\}\\x= \frac{-5+7}{2*6}=\frac{1}{6} \\x= \frac{-5-7}{2*6}=-1$