Question

ayuda
1. (3x-11)²=
2. (2x-3y)²=
9. (x²y²-z³)²= necesito el resultado y el procedimiento ayuda​

Answer 1

Respuesta:

$1. (3x-11)²= {3}^{2} {x}^{2} - 2(3x)(11) + {11}^{2} = 9 {x}^{2} - 66x + 121 \\ 2. (2x-3y)²= {2}^{2} {x}^{2} - 2(2x)(3y) + {3}^{2} {y}^{2} = 4 {x}^{2} - 12xy + 9 {y}^{2} \\ 9. (x²y²-z³)²= {( {x}^{2} )}^{2} { {(y}^{2} )}^{2} - 2( {x}^{2} {y}^{2} )( {z)}^{2} + { {(z}^{3}) }^{2} = {x}^{4} {y}^{4} - 2 {x}^{2} {y}^{2} {z}^{2} + {z}^{6}$