Question

Ejercicios de Binomio al cuadrado, les doy CORONITA
$\: (x + 4) {}^{2} = \\ \ (p + 5q) {}^{2} = \\ (3x + 2) {}^{2} = \\ (5x + 3y) {}^{2} = \\ (3a {}^{2} + x {}^{3} ) { }^{2} =$
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Answer 1

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