Question

ayudame a resolver estas ecuaciones ​

Answer 1

Respuesta:

1. 3x + 2 = 8

3x = 8-2

3x = 6

x = $\frac{6}{3}$

x = 2

2. 6x - 10 = -70

6x = -70 + 10

6x = -60

x = $\frac{-60}{6}$

x = -10

3. $\frac{3x}4}$ + 1 = -20

$\frac{3x}4}$ = -20 - 1

$\frac{3x}4}$ = -21

3x = (-21) . 4

3x = -84

x = $\frac{-84}{3}$

x = -28

4. $\frac{6x}{7}$ - 2 = 10

$\frac{6x}{7}$ = 10 + 2

$\frac{6x}{7}$ = 12

6x = 12 . 7

6x = 84

x = $\frac{84}{6}$

x = 14

5. 9 - 6x = -15

9 = -15 + 6x

15 + 9 = 6x

24 = 6x

$\frac{24}{6}$ = x

4 = x

6. $\frac{x}{3}$ + 2 = 5

$\frac{x}{3}$ = 5 - 2

$\frac{x}{3}$ = 3

x = 3 . 3

x = 9

7. 4x + 13 = 21

4x = 21 - 13

4x = 8

x = $\frac{8}{4}$

x = 2

8. -6x - 4 = 8

-8 - 4 = 6x

-12 = 6x

$\frac{-12}{6}$ = x

-2 = x

9. 2 + $\frac{x}{3}$ = 11

$\frac{x}{3}$ = 11 - 2

$\frac{x}{3}$ = 9

x = 9 . 3

x = 27

10. 5x - 8 = 27

5x = 27 + 8

5x = 35

x = $\frac{35}{5}$

x = 7

Espero te ayude :))