calcula la masa molecular de estos compuestos:
A.Cloruro de magnecio
B.C2H6O
C.C3H6
D.Trióxido de dihierro
E.Nitrato de potasio
Es urgente...por favor me ayudan...
Respuestas
Respuesta dada por:
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a. Mg = 1 x 24 = 24 g/mol
Cl = 2 x 35,4 = 70.8 g/mol
·""""""""""""""""""""""""""""""""""""""""""""
Mm MgCl2 = 94.8 g /mol
b. C = 2 x 12 = 24 g/mol
H = 6 x 1 = 6 g/mol
O = 1 x 16 = 16 g/mol
""""""""""""""""""""""""""""""""""""""""""""
Mm C2H6O = 46 g/mol
c. C = 3 x 12 = 36 g/mol
H = 6 x 1 = 6 g/mol
"""""""""""""""""""""""""""""""""""""""
. Mm C3H6 = 42 g/mol
d. Fe = 2 x 56 = 112 g/mol
O =3 x 16 = 48 g/mol
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Mm Fe2O3= 16o g/mol
e. K = 1 x 39 = 39 g/mol
N = 1 x 14 = 14 g/mol
O = 3 x 16 = 48 g/mol
"""""""""""""""""""""""""""""""""""""""""
Mm KNO3 = 101 g/mol
Cl = 2 x 35,4 = 70.8 g/mol
·""""""""""""""""""""""""""""""""""""""""""""
Mm MgCl2 = 94.8 g /mol
b. C = 2 x 12 = 24 g/mol
H = 6 x 1 = 6 g/mol
O = 1 x 16 = 16 g/mol
""""""""""""""""""""""""""""""""""""""""""""
Mm C2H6O = 46 g/mol
c. C = 3 x 12 = 36 g/mol
H = 6 x 1 = 6 g/mol
"""""""""""""""""""""""""""""""""""""""
. Mm C3H6 = 42 g/mol
d. Fe = 2 x 56 = 112 g/mol
O =3 x 16 = 48 g/mol
""""""""""""""""""""""""""""""""""""
Mm Fe2O3= 16o g/mol
e. K = 1 x 39 = 39 g/mol
N = 1 x 14 = 14 g/mol
O = 3 x 16 = 48 g/mol
"""""""""""""""""""""""""""""""""""""""""
Mm KNO3 = 101 g/mol
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