Question

hola ayuda es para hoy​

Answer 1

Respuesta:

nose

Explicación paso a paso:

perdon

$yaaaaaaaaaaaaa\\x^{2} \geq \neq \pi \pi \neq \neq \int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \sqrt[n]{x} \sqrt[n]{x} \geq \leq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx \geq$