Question

ayudaaaaaaaaaaaaaaaaa​

Answer 1

Respuesta:

2x²+4x+3

Explicación paso a paso:

esa es espero te sirva 7u7

Answer 2

Respuesta:

$\mathbf{\frac{10x^{4}+6x^{3}-37x^{2}+36x-12}{5x^{2}-7x+3}=2x^{2}+4x-3\frac{3x-3}{5x^{2}-7x+3}}$

Explicación paso a paso:

$\frac{10x^{4}+6x^{3}-37x^{2}+36x-12}{5x^{2}-7x+3}=\\\\=\begin{matrix}10x^{4}&+6x^{3}&-37x^{2}&+36x&-12&:&5x^{2}-7x+3=2x^{2}+4x-3\\-10x^{4}&+14x^{3}&-6x^{2}\\\hline0&+20x^{3}&-43x^{2}&+36x\\&-20x^{3}&+28x^{2}&-12x\\\hline&0&-15x^{2}&+24x&-12\\&&+15x^{2}&-21x&+9\\\hline&&0&+3x&-3\end{matrix}$

$q(x)=2x^{2}+4x-3\\\\r(x)=3x-3\\\\\frac{10x^{4}+6x^{3}-37x^{2}+36x-12}{5x^{2}-7x+3}=2x^{2}+4x-3\frac{3x-3}{5x^{2}-7x+3}$