Question

Y=(x-1)^2+1
Hallar vertice
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Answer 1

x^2 - 2x + 4 + 1

x^2 - 2x + 5

a = 1

b = - 2

c = 5

Xv = - b / 2a

Xv = - (-2) / 2 (1)

Xv = 2 / 2

Xv = 1

Yv = (1)^2 +5

Yv = 1 + 5

Yv = 6

(x,y) = (1,6)