Question

alguien que me ayude.!
porfavor ​

Answer 1

Respuesta:

$\sqrt[3]{x} = {x}^{ \frac{1}{3} } \\ \sqrt[4]{ {x}^{5} } = {x}^{ \frac{5}{4} }$

$\sqrt[6]{ {y}^{5} } = {y}^{ \frac{5}{6} } \\ \sqrt[6]{ {a}^{5} {b}^{4} } = {({a}^{5} {b}^{4})}^{ \frac{1}{6} }$

$\sqrt[3]{ { (\frac{2xy}{9x}) }^{4} } = {(\frac{2xy}{9x})}^{ \frac{4}{3} } = \frac{ {(2xy)}^{ \frac{3}{4} } }{ {(9x)}^{ \frac{3}{4} } }$

$\sqrt[4]{ \frac{ {x}^{7} {y}^{12} }{125x} } = {( \frac{ {x}^{7} {y}^{12} }{125x}) }^{ \frac{1}{4} }$