Question

Ayuda por favor :( espara hoyy​

Answer 1

Respuesta:

$\sqrt{ \frac{25}{144} } \sqrt{ \frac{9}{16} } \\ \frac{ \sqrt{25} }{ \sqrt{144} } + \frac{ \sqrt{9} }{ \sqrt{16} } \\ \frac{5}{12} + \frac{3}{4} = \frac{5 + 9}{12} = \frac{14}{12} = \frac{7}{6}$

$( \frac{1}{4} {)}^{3} \div ( \frac{1}{5} {)}^{3} \\ \frac{1}{64} \div \frac{1}{125} = \frac{125}{64}$

$\sqrt{ \frac{16}{25} \times \frac{4}{9} } \times \sqrt{ \frac{1}{4} \times \frac{16}{81} } \\ \frac{ \sqrt{16} }{ \sqrt{25}} \times \frac{ \sqrt{4} }{9} \times \frac{ \sqrt{1} }{ \sqrt{4} } \times \frac{ \sqrt{16} }{ \sqrt{81} } \\ \frac{4}{5} \times \frac{2}{3} \times \frac{1}{2} \times \frac{4}{9} \\ \frac{8}{15} \times \frac{2}{3} \times \frac{1}{2} \times \frac{4}{9} \\ \frac{16}{45} \times \frac{1}{2} \times \frac{4}{9} \\ \frac{8}{45} \times \frac{4}{9} = \frac{32}{405}$

$\sqrt[3]{ \frac{8}{27} } \div ( \frac{3}{2} {)}^{2} \\ \\ \frac{ \sqrt[3]{8} }{ \sqrt[3]{27} } \div \frac{9}{4} \\ \\ \frac{2}{3} \div \frac{9}{4} = \frac{8}{27}$