Question

Resolver a) 3x²-5=33 b) 4√x)+2=30 c) (x+2)³=512 d) √x-8)=5 e) (x²+2):3-2=15 f) 2(√x +1)+8=20

Answer 1

a) 3x²-5=33
3x²=33 +5
3x²=38
x²=38/3
x=√38/3
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b) (4√x)+2=30
4√x=30 -2
4√x=28
√x=28/4
x=7²
x=49
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c) (x+2)³=512
(x+2)=raiz cubica de 512 
x+2=8
x=8-2
x=6
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d) √x-8)=5
x-8=5²
x-8=25
x=25+8
x=33
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e) (x²+2):3-2=15
(x²+2):3=15 +2
(x²+2):3=17
(x²+2)=17(3)
(x²+2)=51
x²=51-2
x²=49
x=√49
x=7
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f) 2(√x +1)+8=20
 2(√x +1)=20-8
2(√x +1)=12
(√x +1)=12:2
(√x +1)=6
√x =6-1
√x =5
x=5²
x=25