Question

¿Me ayudan? Por favor

Answer 1

Respuesta:

$( {a}^{3} - 4 {a}^{2} + 6a)(3ab) = 3 {a}^{4} b - 12 {a}^{3} b + 18 {a}^{2} b$

$( {a}^{2} - 2ab + {b}^{2} )( - ab) = - {a}^{3} b + 2 {a}^{2} {b}^{2} - a {b}^{3}$

$( {x}^{2} + 1 + x)( {x}^{2} - x - 1) = {x}^{4} - {x}^{2} - 2x - 1$

$(2 - 3 {x}^{2} + {x}^{4})( {x}^{2} - 2x + 3) = {x}^{6} - 2 {x}^{5} + 6 {x}^{3} - 7 {x}^{2} - 4x + 6$

$({m}^{3} - 4m + {m}^{2} - 1)( {m}^{3} + 1) = {m}^{6} + {m}^{5} - 4 {m}^{4} + {m}^{2} - 4m - 1$

$({a}^{3} - 5a + 2)( {a}^{2} - a + 5) = {a}^{5} - {a}^{4} + 7 {a}^{2} - 27a + 10$