Question

(secα+cscα)/(secα-cscα)=(senα+cosα)/(senα-cosα)

Answer 1

$(\frac{1}{cos \alpha } +\frac{1}{sen \alpha})(\frac{1}{cos \alpha } -\frac{1}{sen \alpha})$
$(\frac{sen \alpha+cos \alpha}{cos \alpha *sen \alpha})(\frac{sen \alpha-cos \alpha}{cos \alpha *sen \alpha})$