Question

A= 2sen330° - 4sec240° + 2tg(-135°) ayudenme p :(​

Answer 1

Explicación paso a paso:

$\sin(330°) = - \frac{1}{2} \\ \sec(240°) = - 2 \\ \tan( - 135°) = - \tan(135°) = - ( -1 ) = 1$

$A = 2 \sin(330°) - 4 \sec(240°) - 2 \tan( 135°) \\ A = 2( - \frac { 1}{2} ) - 4( - 2) + - 2( - 1) \\ A = - 1 + 8 + 2 \\ A = 9$