Question

a) (x−3)2 +(y+6)2 =25
b) (x−1)2 +(y−2)2 =34
c) (x+2)2 +(y−3)2 =4
d) (x+1)2 +(y+2)2 =16




a) x2 +y2 −4x+2y−1 =0
b) x2 +y2 −2x−4y−29 =0
c) x2 + y2 + 6x + 9 = 0
d) x2 +y2 −8x−10y+25 =0


Alguien me ayuda a resolver esto por favor?

Answer 1

alguien yo también necesito esta?

Answer 2

Respuesta:

a) (x−3)2 +(y+6)2 =25

2(x−3)+(y+6)×2=25

2(x−3)+2(y+6)=25

2(x−3+y+6)=25

x-3+y+6=25/6

x+y+3=25/2

x+3=25/2 -y

b) (x−1)2 +(y−2)2 =34

2(x-1)+(y-3)×2=4

2(x-1)+2(y-3)=4

2(x-1+y-3)=4

c) (x+2)2 +(y−3)2 =4

2(x+1)+(y+2)×2=16

2(x+1)+2(y+2)=16

2(x+1+y+2)=16

x+1+y+2=16/2

x+1+y+2=8

d) (x+1)2 +(y+2)2 =16

2(x+1)+(y+2)×2=16

2(x+1)+2(y+2)=16

2(x+1+y+2)=16

x+1+y+2=16/2

x+1+y+2=8

x+1+y+2=8

x+y+3=8

x+y+3=8

x+3=8-y

x=8-y-3

x=5-y

d) (x+1)2 +(y+2)2 =16

2(x+1)+(y+2)×2=16

2(x+1)+2(y+2)=16

2(x+1+y+2)=16

x+1+y+2=16/12

x+1+y+2=8

x+y+3=8

x+3=8-y

x=8-y-3

x=5-y