Question

K=(sen30.cos60+tg60.cos30)\(sen37+tg37)

Answer 1

k = [sen(30)cos(60) + tg(60)cos(30)] / [sen(37) + tg(37)]

k = [0,25 + 1,5] / [0,6 + 0,75]

k = 1,75 / 1,35

k =.1,3