Question

4(x)^2 + 4(y)^2 - 4x - 8y - 11=0

ayuda xfi.

Answer 1

4 x² + 4 y² - 4 x - 8 y - 11= 0

(4x²-4x) +(4y²-8y) =11

4x(x-1) + 4y (y-2) =11

4 {x(x-1) + y(y-2)} = 11