Question

Como resuelvo esta ecuacion logaritmica??

Answer 1

Respuesta:

$1)log_{2}(x) = - 1 \\ {2}^{ log_{2}(x) } = { 2}^{ - 1} \\ x = \frac{1}{2}\\2)log (x+1)-log x=1\\\frac{ log(x + 1) }{ log(x) } = 1 \\ \frac{ {10}^{ log(x + 1) } }{ {10}^{ log(x) } } = {10}^{1} \\ \frac{x + 1}{x} = 10 \\ x + 1 = 10x \\ 1 = 10x - x \\ 1 = 9x \\ x = \frac{1}{9}$