Question

(3a^2-1)(-3a^2+5)=
urgenteeeee

Answer 1

Respuesta:

$(3 {a}^{2} - 1)( {- 3a }^{2} + 5) = \\ - {9a }^{4} + 15 {a}^{2} + 3 {a}^{2} - 5 = \\ - 9 {a}^{4} + 17 {a}^{2} - 5 = 0 \\ {a}^{2} (9 {a}^{2} + 17) - 5 = 0$